# Determinant of a 3 x 3 Matrix

In matrices, determinants are the special numbers calculated from the square matrix. The symbol used to represent the determinant is represented by vertical lines on either side.

Let A be the matrix, then the determinant of a matrix A is denoted by |A|. To find any matrix such as determinant of 2×2 matrix, determinant of 3×3 matrix, or n x n matrix, the matrix should be a square matrix. It means that the matrix should have an equal number of rows and columns. Find determinants of a matrix are helpful in solving the inverse of a matrix, a system of linear equations, and so on.

## Determinant of a 3 x 3 Matrix Formula

We can find the determinant of a matrix in various ways. If we break the smaller 2 x 2 determinant problems as it is easy to handle, we can find the determinant of a 3 x 3 matrix.

Let’s suppose you are given a square matrix C where

C = $$\begin{bmatrix} a & b &c \\ d& e &f \\ g& h &i \end{bmatrix}$$

Let’s calculate the determinant of matrix C,

Det $$\begin{bmatrix} a & b &c \\ d& e &f \\ g& h &i \end{bmatrix}$$

= a. det $$\begin{bmatrix} e & f\\ h & i \end{bmatrix}$$ – b.det $$\begin{bmatrix} d & f\\ g & i \end{bmatrix}$$ + c . det $$\begin{bmatrix} d & e\\ g & h \end{bmatrix}$$

### Few Important points on 3x 3 Determinant Matrix

• The scalar multipliers to a corresponding 2 x 2 matrix have top row elements a, b and c serving to it.
• The scalar element gets multiplied by 2 x 2 matrix of remaining elements created at the time when vertical and horizontal line segments were drawn through passing through a.
• This is how we construct the 2 by 2 matrices for scalar multipliers b and c.

The determinant of 3 x 3 matrix formula is given by,

$$\begin{bmatrix} a & b &c \\ d& e &f \\ g& h &i \end{bmatrix}$$ = $$\begin{bmatrix} 2 & -3 &9 \\ 2 & 0 & -1\\ 1& 4 & 5 \end{bmatrix}$$

## Determinant of the 3 x 3 Matrix Examples

### Example 1:

Calculate the determinant of the 3 x 3 matrix.

$$\begin{bmatrix} 2 & -3 &9 \\ 2 & 0 & -1\\ 1& 4 & 5 \end{bmatrix}$$

Solution:

Let’s find the correspondence between the generic elements in the formula and elements of real problem.

$$\begin{bmatrix} a & b &c \\ d& e &f \\ g& h &i \end{bmatrix}$$ = $$\begin{bmatrix} 2 & -3 &9 \\ 2 & 0 & -1\\ 1& 4 & 5 \end{bmatrix}$$

Use the 3 x 3 determinant formula:

Applying the formula,

= 2[ 0 – (-4)] + 3 [10 – (-1)] + 3 [10 – (-1)] +1 [8-0]

= 2 (0+4) +3 (10 +1) + 1(8)

= 2(4) +3(11) + 8

= 8+33+8

= 49

Therefore, the determinant of $$\begin{bmatrix} 2 & -3 &9 \\ 2 & 0 & -1\\ 1& 4 & 5 \end{bmatrix}$$ = 49

### Example 2:

Calculate the determinant of the 3 x 3 matrix.

$$\begin{bmatrix} 1 & 3 &2 \\ -3 & -1 & -3\\ 2& 3 & 1 \end{bmatrix}$$

Solution:

Let’s find the correspondence between the generic elements in the formula and elements of real problem.

$$\begin{bmatrix} a & b &c \\ d& e &f \\ g& h &i \end{bmatrix}$$ = $$\begin{bmatrix} 1 & 3 &2 \\ -3 & -1 & -3\\ 2& 3 & 1 \end{bmatrix}$$

Use the 3 x 3 determinant formula:

= 1[ -1 – (-9)] – 3 [-3 – (-6)] + 2 [-9 – (-2)]

= 1 (-1+9) -3 (-3 +6) + 2(-9 + 2)

= 1(8) -3(3) +2(-7)

= 8 -9-14

= -15

Therefore, the determinant of $$\begin{bmatrix} 1 & 3 &2 \\ -3 & -1 & -3\\ 2& 3 & 1 \end{bmatrix}$$ =-15