The multiplicative inverse of a number for any n is simply 1/n. It is denoted as

**x = 1 / x (or) x = x ^{-1} (Inverse of x)**

It is also called as the reciprocal of a number and **1 is called the multiplicative identity**.

Consider the examples,

The multiplicative inverse of 2 is given as 1 / 2.

But in this case, the **multiplicative inverse of 0 is infinite**. Because

1/0 = infinity

So, there is no reciprocal for a number ‘0’.

Finding the multiplicative inverse of natural numbers is easy, but it is difficult for complex and real numbers.

The product of a number and its multiplicative inverse is 1.

x. x^{-1} = 1

For example, consider the number 13.

The multiplicative inverse of 13 is 1/13.

According to the property,

13. (1/13) = 1

Hence Proved.

**Proof:**

**Method 1: **For the given two integers say ‘a’ and ‘m’, find the modular multiplicative inverse of ‘a’ under modulo ‘m’.

The modular multiplicative inverse of an integer ‘x’ such that.

ax ≡ 1 ( mod m )

The value of x should be in the range of {0, 1, 2, … m-1}, i.e., it should be in the ring of integer modulo m.

Note that, the modular reciprocal exists, that is “a modulo m” if and only if a and m are relatively prime.

gcd(a, m) = 1.

**Method 2:**

If a and m are coprime, multiplicative inverse modulo can also be found using the Extended Euclidean Algorithm

From the Extended Euclidean algorithm, that takes two integers to say ‘a’ and ‘b’, finds their gcd and also find ‘x’ and ‘y’ such that

ax + by = gcd(a, b)

To find the reciprocal of ‘a’ under ‘m’, substitute b = m in the above formula. We know that if a and m are relatively prime, the value of gcd is taken as 1.

ax + my = 1

Take modulo m on both sides, we get

ax + my = 1(mod m)

We can remove the second term on the left side as ‘my (mod m)’ because for an integer y will be 0. So it becomes,

ax ≡ 1 (mod m)

So, the value of x can be found using the extended Euclidean algorithm which is the multiplicative inverse of a.

It mostly used in equations for simplifications. Mostly it is used for cancellation of the terms. Remember that if you want to find the multiplicative inverse of a number then take the reciprocal of a number.

Find reciprocal is quite difficult for complex numbers and real numbers. When you consider both the numbers, there is a significant similarity. However, when you are dealing with rational expressions, there is an instance of having a radical (or) square root in the denominator part of the expression.

Consider an example,

\(2/\sqrt{3}+2\)

The radicals in the denominator make the fraction more complex. In order to remove the radical in the denominator, it is needed to manipulate the fraction. To simplify the fraction, multiply the entire fraction by the conjugate. It means that conjugates are like their counterparts, but the signs between the parts should be different.

Therefore, it becomes,

\(\frac{2}{\sqrt{3}+2}\times \frac{\sqrt{3}-2}{\sqrt{3}-2}\) \(\frac{2\sqrt{3}-4}{3-4}\) \(-(2\sqrt{3}-4)\)

If there is any minus sign inside the radical part, then take the minus outside and substitute with the letter i.

For example,

\(4+\sqrt{-3}\)

It can be written as

\(4+i\sqrt{3}\)

Where the second part is called the imaginary part.

**Example 1 :**

Find the multiplicative inverse of -5

**Solution :**

The reciprocal of -5 is -1 / 5

**Check** : Number x Multiplicative inverse = 1

(-5) x (-1/5) = 1

1 = 1

So, the multiplicative inverse of -5 is -1 / 5.

**Example 2 :**

Find the reciprocal of 7/74

**Solution :**

Multiplicative inverse of 7/74 = (1/7) / (1/74)

= 74/7

**Check** : Number x Multiplicative inverse = 1

(7/74) x (74/7) = 1

Therefore, the solution is 74/7.